Medvedev is eliminated in the fourth round of the Indian Wells tournament

Russian tennis player Daniil Medvedev lost to Bulgarian Grigor Dimitrov in the fourth round of the tournament in Indian Wells (USA), according to Sport-Express.

The meeting took place on October 13 and ended in three sets with a score of 6: 4, 4: 6, 3: 6. At the same time, Medvedev was leading in the second set with a break (6: 4, 4: 1), after which he twice gave his own serve.

The duration of the match was two hours and 16 minutes. During this time, the Russian has filed right through five times, made six double faults and converted five break points out of seven.

Dimitrov, who is the 28th racket in the world, made one ace, made a mistake four times on the second serve and took the opponent’s serve six times out of ten such chances.

At the Indian Wells tournament, there were no Russians left in the men’s singles draw. Earlier that day, at the stage of the fourth round, Karen Khachanov lost to Georgian tennis player Nikoloz Basilashvili. Prior to that, Aslan Karatsev lost in the 1/8 finals, and Andrei Rublev flew out in the 1/16 finals.

Daniil Medvedev has been in second place in the rating of the Association of Tennis Professionals (ATP) since May. Next week, he is expected to perform at the Kremlin Cup in Moscow (October 18-24).